silas

At what distance from a long, straight wire

carrying a current of 5 A is the magnetic field

due to the wire equal to the strength of the

Earth’s field, approximately 4 × 10^−5 T ?

Answer in units of cm.

A wire 24.5 cm long is at right angles to a

0.317 T uniform magnetic field. The current

through the wire is 6.72 A.

What is the magnitude of the force on the

wire?

Answer in units of N

pt 1 

 Four long, parallel conductors carry equal2 A currents, oriented at the corners of asquare with sides of length of 0.5 m . A crosssectional view of the conductors is shown.The current direction is out of the page atpoints indicated by the dots and into the pageat points indicated by the crosses.

pt2

What is the magnitude of any of the equal

magnetic field components BA , BB , BC , or

BD at the point P?

Answer in units of T.

pt3

What is the magnitude of the total magnetic

field at point P?

Answer in units of T.

please help thanks you 

At what distance from a long, straight wire

carrying a current of 6 A is the magnetic field

due to the wire equal to the strength of the

Earth’s field, approximately 6 × 10^−5 T ?

Answer in units of cm.

A thin, horizontal copper rod is 0.859043 m

long and has a mass of 37.2406 g.

The acceleration of gravity is 9.8 m/s^2

What is the minimum current in the rod

that will cause it to float in a horizontal magnetic field of 1.73829 T?

Answer in units of A.

A wire 24.5 cm long is at right angles to a

0.317 T uniform magnetic field. The current

through the wire is 6.72 A.

What is the magnitude of the force on the

wire?

Answer in units of N.

Suppose a new particle is discovered, and it is found that a beam of these particles passes undeflected through “crossed” electric and magnetic fields, where E = 471 V/m and B = 0.00151 T. If the electric field is turned off, the particles move in the magnetic field in circular paths of radius r = 2.89 cm.

Determine q/m

for the particles from these data.

Answer in units of C/kg

A 2 cm length of tungsten filament in a small

lightbulb has a resistance of 0.08 Ohms 

Find its diameter. The resistivity of the

filament is 5.6 × 10^−8 Ohms  · m

Answer in units of mm

A positive test charge of 7.45 × 10^−5 C is

placed in an electric field of 51.42 N/C intensity.

What is the strength of the force exerted on

the test charge?

Answer in units of N

A positive test charge of 7.45 × 10^−5 C is

placed in an electric field of 51.42 N/C intensity.

What is the strength of the force exerted on

the test charge?

Answer in units of N.

Two identical conducting spheres are placed

with their centers 0.21 m apart. One is given

a charge of +1.2 × 10−8 C and the other a

charge of −1.6 × 10−8 C.

Find the magnitude of the electric force

exerted by one sphere on the other.

The value of the Coulomb constant is

8.98755 × 109 N · m2

/C

2

.

Answer in units of N.

part 2 ?

The spheres are connected by a conducting

wire.

After equilibrium has occurred, find the

electric force between them.

Answer in units of N

pt1 

Two identical conducting spheres are placedwith their centers 0.21 m apart. One is givena charge of +1.2 × 10−8 C and the other acharge of −1.6 × 10−8 C.Find the magnitude of the electric forceexerted by one sphere on the other.The value of the Coulomb constant is8.98755 × 109 N · m2/C2.Answer in units of Npt 2   The spheres are connected by a conductingwire.After equilibrium has occurred, find theelectric force between them.Answer in units of N.

part 1 A bullet of mass 2 g moving with an initial

speed 500 m/s is fired into and passes through

a block of mass 6 kg, as shown in the figure.

The block, initially at rest on a frictionless,

horizontal surface, is connected to a spring of

force constant 599 N/m. If the block moves a distance 0.68 cm to the

right after the bullet passed through it, find

the speed v at which the bullet emerges from

the block.

Answer in units of m/s.

part 2 Find the magnitude of the energy lost in the

collision.

Answer in units of J.

part 1 A 580 kg mass is sliding on a horizontal frictionless surface with a speed of 9.5 m/s when

it collides with a 82 kg mass initially at rest,

as shown. The masses stick together and slide

up a frictionless track at 60◦

from horizontalWhat is the speed of the two blocks immediately after the collision? The acceleration

due to gravity is 9.8 m/s

2

.

Answer in units of m/s.

part 2 After the collision, the masses slide up the

incline. To what maximum height h above the horizontal surface will the masses slide?

Answer in units of m

thank you for the help whoever does this have a blessed day 

An 8 g bullet is fired into a 319 g block that

is initially at rest at the edge of a frictionless

table of height 1.1 m. The bullet remains in

the block, and after impact the block lands

1.7 m from the bottom of the table. Find the initial speed of the bullet. The

acceleration due to gravity is 9.8 m/s ^2

.

Answer in units of m/s.

A 4.15 g bullet is fired vertically into a 1.98 kg

block of wood.

The bullet gets stuck in the block, and the

impact lifts the block 0.074 m up. (That is,

the block — with the bullet stuck in it — rises

0.074 m up above its initial position, and then

falls back down.)

Given g = 9.8 m/s ^2

. What was the initial

velocity of the bullet?

Answer in units of m/s

A rocket is fired vertically upward. At the

instant it reaches an altitude of 2720 m and a

speed of 296 m/s, it explodes into three equal

fragments. One fragment continues to move

upward with a speed of 250 m/s following the

explosion. The second fragment has a speed

of 476 m/s and is moving east right after the

explosion.

What is the magnitude of the velocity of

the third fragment?

Answer in units of m/s.

An 8 g bullet is fired into a 319 g block that

is initially at rest at the edge of a frictionless

table of height 1.1 m. The bullet remains in

the block, and after impact the block lands

1.7 m from the bottom of the table. Find the initial speed of the bullet. The

acceleration due to gravity is 9.8 m/s ^2

.

Answer in units of m/s.

A 4.15 g bullet is fired vertically into a 1.98 kg

block of wood.

The bullet gets stuck in the block, and the

impact lifts the block 0.074 m up. (That is,

the block — with the bullet stuck in it — rises

0.074 m up above its initial position, and then

falls back down.)

Given g = 9.8 m/s ^2

. What was the initial

velocity of the bullet?

Answer in units of m/s

A rocket is fired vertically upward. At the

instant it reaches an altitude of 2720 m and a

speed of 296 m/s, it explodes into three equal

fragments. One fragment continues to move

upward with a speed of 250 m/s following the

explosion. The second fragment has a speed

of 476 m/s and is moving east right after the

explosion.

What is the magnitude of the velocity of

the third fragment?

Answer in units of m/s.

A space station in the form of a large wheel,

112 m in diameter, rotates to provide an “artificial gravity” of 8.8 m/s

2

for people located

on the outer rim.

Find the rotational frequency of the wheel

that will produce this effect.

Answer in units of rpm

A space station in the form of a large wheel,

281 m in diameter, rotates to provide an “artificial gravity” of 4.6 m/s

2

for people located

on the outer rim.

Find the rotational frequency of the wheel

that will produce this effect.

Answer in units of rpm

According to the Guinness Book of World

Records (1990 edition, p. 169), the highest

rotary speed ever attained was 2010 m/s (4500

mph). The rotating rod was 15.3 cm (6 in)

long. Assume the speed quoted is that of the

end of the rod.

What is the centripetal acceleration of the

end of the rod?

Answer in units of m/s

2

If you were to attach a(n) 2.29 g object to the

end of the rod, what force would be needed to

hold it on the rod?

What is the period of rotation of the rod?

Answer in units of s.

An amusement park ride consists of a large

vertical cylinder that spins about its axis fast

enough that a person inside is stuck to the

wall and does not slide down when the floor

drops away.

The acceleration of gravity is 9.8 m/s

2

.

Given g = 9.8 m/s

2

, the coefficient µ =

0.614 of static friction between a person and

the wall, and the radius of the cylinder R =

5.2 m. For simplicity, neglect the person’s

depth and assume he or she is just a physical

point on the wall. The person’s speed is

v =

2πR

T

where T is the rotation period of the cylinder

(the time to complete a full circle).

Find the maximum rotation period T of the

cylinder which would prevent a 73 kg person

from falling down.

Answer in units of s.