animalz

I have some answers but I want to know if I'm correct, I just need a quick outline of how to answer question 8:

https://docs.google.com/file/d/0Bx0pPxTi8WJLUFNNMT...

cheers

I think mean square is a measure of variation, but I'm not so sure about 'sum of squares', is it similar in defniniton to 'mean square'?

cheers

You are working for a biotech company in Sydney that is developing herbivore deterrents

derived from predator urine. The company has developed a new product designed to deter

wallabies from feeding on treated trees to help improve tree survival in reforestation efforts as

part of a carbon-trading scheme. They ask you to determine if their new product (X) is better

at deterring wallabies than two other traditional compounds (A, B) used by their competitors.

For each compound, you determine the mean number ofleaves chewed on seedlings in a

wallaby enclosure. For the different treatments, n=15 seedlings are coated with the relevant

deterrent compound, and the key response is the leaves chewed by wallabies on replicate

seedlings after 2 days. The mean numbers of leaves chewed per seedling for the treatments

were: X=3.2, A=5.2, B=7.2. All of the assumptions for an ANOVA were fulfilled by the

data. ANOVA on the data gave a residual (within) sums of squares of 1.90.

a) Draw up an ANOVA table and complete it as far as possible with the data provided

above. Give your calculations. 10 marks

I don't know how to fill in the table if I'm not given the raw data, any help would be great, cheers

Hi I got a question for my assignment, and it involves a goodness of fit test.

A behavioural ecologist was studying Gouldian Finches. They

occur in three colour morphs with yellow, red and black faces.

The black faced morph is common (70% of individuals in the

wild), the red morph (moderately common, 29%) and the yellow

morph rare (1%). As the finches are an endangered species,

she used individuals sourced from captive populations in her

experiments and needed to test whether the colour morphs

were in similar proportions as the field populations. Her captive

population had 150 birds: 96 black, 49 red, and 5 yellow faced.

The researcher was also concerned about possible sex biases in her experiments. The red

birds included 30 males and 19 females.

8d) Does the sex ratio in the red birds differ from an expected equal number of males and

females? How many males would need to be in the sample of 49 birds to obtain a significant

chi squared test?

Can someone explain to me what's happening?

Cheers

I've taken a SRS of 50 movie titles and i've seen 11 out of 50, so my p-hat is 0.22 (proportion)

If my lecturers estimate was 54%, does this mean his proportion was 0.54, as in he saw 27 out of 50 for his SRS?

and also, for the method of inference, would i do a one sample test for p? the question asks, is there evidence the percentage i've seen is different? so would my null hypothesis be: my percentage is equal to my lecturers? and would my actual hypothesis be the my percentage is different? how would i show this? and what do these mean:

If Ha:p>po then the P-value = P(Z>z)

If Ha:p<po then the P-value = P(Z<z)

If Ha:p not equal to po then the P-value = 2P[Z>z(abs value)]

i'm just getting confused as to the methods and order i do them and how to interperet everything,any help would be great, thx!