Daughter's math homework has me stumped!!!?

n

_

3n-1

or n/3n-1 if you want to look at it another way.

to find the nth number you need a formula (equation)

the num,erator is the top number and it increases by 1

the denominator is the bottom number and it goes up by 3

so for the top we start with 1 and add 1 for each n

numerator = 1 + 1(n-1) thats so for n = 1 we get 1

denominator will be 2 + 3(n-1) THE -1 adjusts for the start

since it is the first number + a value for each step.

(1+ (n-1))/(2+3(n-1)) = q is the answer

so n = 1 q = 1/2

n= 2 q = 2/5

see that wasnt that hard :-)

1/2 2/5 3/8 4/11 5/14 6/17 7/20 8/23 9/24

1+1=2

2+3=5 hence 2/5 etc.

Answer = 9/24

Equinox has it right.

n/3n-1

the top number is just adding one each time, so it will always be n

the bottom is done by adding three so it is determined by 3n.

since the starting point was 1/2, you need to subtract 1 to get the 2 in the denominator.

If the starting term had be 3/5 for example then you need to do (n+2)/(3n+2). The addition and subtraction of terms is just to accommodate the starting point. You use multiplication to get to each next term.

the nth term is...

n / 2n+1

try it out, it works :D

oh, it helps to have what number of sequence each fraction is

e.g. 1/2 is 1 2/5 is 2 etc.

9/23

I agree with Equinox and Bekki.

n/(3n-1) or 9/(3x9-1) = 9/26

well just keep adding one to the number in front of the / and adding 3 to each number behind the /