How many moles of sodium ions are present in 2.67 moles of sodium sulfate?

To answer this question, first one must get the chemical formula from the nomenclature.

Sodium, represented by the chemical symbol Na, always supplies a charge of +1, as it is in the first column on the elemental table. Sulfate, a polyatomic compound is made from one sulfur atom and four oxygen atoms (together represented by the formula SO4), and always supplies a charge of -2.

It also must be known that sodium sulfate is a neutral compound, meaning the combined charge of the sodium and the sulfate in the compound adds up to be 0.

Therefore, you must add 2 sodium atoms or every sulfate ion present in each unit of sodium sulfate. You end up with a chemical formula of Na2SO4.

So if you have 2.67 moles of sodium sulfate, and for every particle of sodium sulfate you have 2 sodium ions, it is safe to say that for every mole of sodium sulfate that you would have 2 moles of sodium ions, therefore if you have 2.67 moles of sodium sulfate, you should get 5.34 moles of sodium ions present.

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Sodium Chloride - NaCl Sodium Sulfate - Na_2_SO_4_ as a consequence, once you have 0.6 mol of chloride ions, you will possibly have 0.6 mol of sodium present day interior the NaCl with the aid of fact the ratio of the ions is a million:a million. once you have 0.2 mol of sulfate ions, you will possibly have 0.4 mol of sodium present day interior the Na2SO4 with the aid of fact there are two times as many sodium ions as sulfate ions interior the compound. In entire, you will possibly have 0.6 mol Na + 0.4 mol Na = a million.0 mol Na