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Help with this algebra question Find the third, seventh, and tenth terms of each sequence:?
Find the third, seventh, and tenth terms of each sequence:
A (n)=10+(n-1)(4)
A (n)=12+(n-1)(-4)
A (n)=1.2(n-1)(-4)
A (n)=-5+(n-1)(2)
A (n)=8+(n-1)(3)
A (n)=8+(n-1)(-3)
4 Answers
- 10 years agoFavourite answer
A (n)=10+(n-1)(4) - 3rd Term = 10+2*4 = 18, 5th Term = 10+4*4 = 26, 7th Term = 10+6*4 = 34
A (n)=12+(n-1)(-4) - 3rd Term = 12+2*-4 = 4, 5th Term = 12+4*-4 = -4, 7th Term = 12+6*-4 = -12
A (n)=1.2(n-1)(-4) - 3rd Term = 1.2*2*-4 = -9.6, 5th Term = 1.2*4*-4 = -19.2, 7th Term = 1.2*6*-4 = -28.8
A (n)=-5+(n-1)(2) - 3rd Term = -5+2*2 = -1, 5th Term = -5+4*2 = 3, 7th Term = -5+6*2 = 7
A (n)=8+(n-1)(3) - 3rd Term = 8+2*3 = 14, 5th Term = 8+4*3 = 20, 7th Term = 8+6*3 = 26
A (n)=8+(n-1)(-3) - 3rd Term = 8+2*-3 = 2, 5th Term = 8+4*-3 = -4, 7th Term = 8+6*-3 = -10
- RameshwarLv 710 years ago
A (n) = 10 + (n-1) (4)
(A) (3) = 10+8 =18, (A) (7) = 34 , A(10) += 46------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- A (n) = 12+(n-1) (-4)
third = 4 , seventh = -12 , 10 th = - 24----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- A (n) =1.2 (n-1) (-4)
3rd = - 9.6 , 7th = - 28.8 , 10th = 43.2------------------------------------------------------------------------------------------------------ A(n) = -5 + (n-1) (2)
3rd = - 1 7th = 7 10th = 14------------------------------------------------------------------------------------------------------------------------- A (n) = 8 +(n-1) (3)
3rd =14, 7th = 26 , 10th = 35 ----------------------------------------------------------------------------------------------------------- A (n) = 8 + (n-1) (-3)
3rd = 2 , 7th = -10 , 10 th = -19
- ?Lv 45 years ago
take 18 from fifty 4, it relatively is comparable to 36, there are 9 words from 3 to twelve. Divide 36 with the help of 9, it relatively is comparable to 4. Multiply 4 with the help of seven because of the fact the order of the words is they are going up with the help of 4s. it relatively is comparable to 20-eight
