Magnitude of the force?

Question

1) what is the magnitude of force (F) ?

2) what is the magnitude of the force the pivot exerts on rod at point 0 ?

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10 points for first correct answer

Anonymous · Accepted Answer

1. 
resolving forces perpendicular to rod:
5.7*cos(33) = F*sin(53-33)

F = 5.7*cos(33) / sin(20) = 13.977 N (3dp)

2. 
resolving forces parallel to rod
5.7*sin(33) - 13.977*cos(20) = -10.030 (3dp)

therefore the forces acting on the rod are pulling the rod away from the pivot with a force of roughly 10 N, so the pivot will have to exert a force of 10 N as well in the opposite direction to oppose those forces.

answer = 10.030 N (3dp)

Magnitude of the force?

1 Answer