Can u solve these 2 equations without calculator?

9^(x+1) = 27^(x-1)

(3^2)^(x+1)= (3^3)^(x-1)

3^2(x+1)= 3^3(x-1)

2(x+1)=3(x-1)

2x+2=3x-3

x=5

4^(x+1) = 16^(2x)

(2^2)^(x+1)=(2^4)^(2x)

2^2(x+1)= 2^(8x)

2(x+1)=8x

2x+2=8x

6x=2

x=1/3

This presentation is rather misleading.

Will take a guess at :-

Qu1

3.9^(x + 1) = 27^(x - 1)

3.3^(2x + 2) = 3^(3x - 1)

3^(2x + 3) = 3^(3x - 1)

2x + 3 = 3x - 1

4 = x

Qu 2

2.4^(x+1) = 16^(2x)

2 [ 2^(2x + 2) ] = 2^(8x)

2^(2x + 3) = 2^(8x)

2x + 3 = 8x

3 = 6x

x = 1/2

Will have another guess as to how questions are meant to read:-

Qu 1

[ 9^(x + 1) ] = 27^(x - 1)

[ 3^(2x + 2) ] = 3^(3x - 3)

2x + 2 = 3x - 3

5 = x

Qu 2

4^(x + 1) = 16^(2x)

4^(x + 1) = 4^(4x)

x + 1 = 4x

1 = 3x

x = 1/3

PS

Out of interest could you clarify how questions were meant to be read?

(3)9^(x+1) = 27^(x-1)

or 3^2( x+1) = 3^3( x-1)

or 2(x+ 1) = 3 ( x- 1 )

or 2x + 2 = 3x -3

or x= 5 ans

proof ------------------------------------

9^(5+1) = 9^6 = (3^2)^6 = 3^12

27^(5-1) =27^4 = (3^3)4 = 3^12

(2) 4^(x+1) = 16^(2x)

or 4^(x+1) = 4^2*2x= 4^4x

or x+ 1 = 4x

or x= 1/3 ans

proof-------------

4^(1/3+ 1) =4^4/3

16^( 2*1/3) = 4^2*2/3= 4^4/3

3.9^(x+1) = 27^(x-1) OR 3^(2x + 3) = 3^(3x -- 3) whence 3x -- 3 = 2x + 3 OR x = 6 ANSWER

2.4^(x+1) = 16^(2x) OR 2^(2x + 3) = 2^(8x) whence 8x = 2x + 3 OR 6x = 3 OR x = 1/2 ANSWER

no