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Arthur
Arthur asked in Science & MathematicsChemistry · 5 months ago

Chemistry 3 ?

Consider the combustion of butane (C4H10):

 

2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(l)

 

In a particular reaction, 5.85 moles of C4H10 are reacted with an excess of O2. Calculate the number of moles of CO2 formed.

 

 mol CO2

1 Answer

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  • Roger the Mole
    Lv 7
    5 months ago

    (5.85 mol C4H10) x (8 mol CO2 / 2 mol C4H10) = 23.4 mol CO2

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