Yahoo Answers is shutting down on 4 May 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
1 Answer
- Roger the MoleLv 71 month ago
Ca(OH)2 + H2SO4 → CaSO4 + 2 H2O
(31.0 g H2SO4) / (98.0791 g H2SO4/mol) = 0.31607 mol H2SO4
(26.7 g Ca(OH)2) / (74.0927 g Ca(OH)2/mol) = 0.36036 mol Ca(OH)2
0.31607 mole of H2SO4 would react completely with 0.31607 mole of Ca(OH)2, but there is more Ca(OH)2 present than that, so Ca(OH)2 is in excess and H2SO4 is the limiting reagent.
(0.31607 mol H2SO4) x (1 mol CaSO4 / 1 mol H2SO4) x (136.1406 g CaSO4/mol) =
43.0 g CaSO4 formed
((0.36036 mol Ca(OH)2 initially) - (0.31607 mol Ca(OH)2 reacted)) x
(74.0927 g Ca(OH)2/mol) = 3.28 g Ca(OH)2 remains
