Yahoo Answers is shutting down on 4 May 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
2 Answers
- ?Lv 71 month ago
sqr[(r(r^2-3))^2-4]/(r^2-1)
=
sqr[(r^4-6r^2+9)r^2-4]/(r^2-1)
=
sqr[r^6-6r^4+9r^2-4]/(r^2-1)
=
sqr[(r^2-1)(r^4-5r^2+4)]/(r^2-1)
=
sqr[(r^2-1)(r^2-4)(r^2-1)]/(r^2-1)
=
sqr[(r^2-4)(r^2-1)^2]/(r^2-1)
=
(r^2-1)sqr(r^2-4)/r^2-1)
=
sqr(r^2-4)
This proves that my previous result in another problem
x+y+z=
(3/2){r+/-sqr[(r(r^2-3))^2-4]/(r^2-1)} is exactly=
(3/2)[r+/-sqr(r^2-4)]
That is what I actually want.
Stars are awarded to those who
successfully solves the problem.
- rotchmLv 71 month ago
What is strange is that you're a level 7 here and you even solve much much harder problems like differential equations and calculus. Yet you're asking to solve a very easy algebra question?
Anw, hint: Square both sides. ]
So, is it true?
Or, can you find a counterexample?
