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What is the solution to this math word problem?
The Quality Mushroom Company sells small mushrooms for $5.95 per pound and large mushrooms for $6.95 per pound. How many pounds of large mushrooms should be mixed with 2 pounds of small ones in order to create a mixture that sells for $6.75 per pound?
2 Answers
- KrishnamurthyLv 74 weeks ago
The Quality Mushroom Company sells
small mushrooms for $5.95 per pound and large mushrooms for $6.95 per pound. How many pounds of large mushrooms should be mixed with
2 pounds of small ones in order to create a mixture that sells for $6.75 per pound?
Let x be the number of pounds of large mushrooms.
2 * 5.95 = 11.90
11.90 + 6.95x
(11.90 + 6.95x) / (x + 2) = 6.75
11.90 + 6.95x = 6.75(x + 2)
11.90 + 6.95x = 6.75x + 13.50
0.20x = 1.60
x = 1.6 / 0.2
x = 8
You need 8 pounds of large mushrooms.
- llafferLv 74 weeks ago
Let x = number of pounds of large mushrooms.
You want $6.75 per pound so you need to divide the total cost divided by the total pounds.
We know there is 2 pounds of small at $5.95 per pound, so that's a total cost of:
2 * 5.95 = 11.90
Add that to $6.95 per pound for "x" pounds for the total cost:
11.90 + 6.95x
Then divide that by the total number of pounds (x + 2), and set it equal to 6.75:
(11.90 + 6.95x) / (x + 2) = 6.75
Now we can solve for x. Start by multiplying both sides by (x + 2):
11.90 + 6.95x = 6.75(x + 2)
11.90 + 6.95x = 6.75x + 13.50
0.20x = 1.60
x = 1.6 / 0.2
x = 8
You need 8 pounds of large mushrooms.